Get Answers to all your Questions

header-bg qa

An electric dipole with  4 \times 10^{-9} \mathrm{~cm} is aligned at  30^{\circ} with the direction of a uniform electric field of magnitude 5 \times 10^{+4} \mathrm{NC}^{-1} , the magnitude of the torque acting on the dipole is-

Option: 1

10^{-5} \mathrm{Nm}


Option: 2

10^{-4} Nm


Option: 3

10 \times 10^{-3} \mathrm{Nm}


Option: 4

\sqrt{3} \times 10^{-4} \mathrm{Nm}


Answers (1)

best_answer


\mathrm{\tau =P E \sin \theta }
\mathrm{ =4 \times 10^{-9} \times 5 \times 10^{+4} \times \sin 30^{\circ} }
\mathrm{=20 \times 10^{-5} \times \frac{1}{2}=10^{-4} \mathrm{~Nm}}

Posted by

Ritika Harsh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE