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  • An electromagnetic wave of frequency 1x1014 hertz is propagating along the z-axis. The amplitude of the electric field is 4 V/m.If <img alt="\epsilon _{0}" src="https://entrancecorner.on

An electromagnetic wave of frequency 1x1014 hertz is propagating along the z-axis. The amplitude of the electric field is 4 V/m.If \epsilon _{0} = 8.8 x 10-12 C2/N-m2, then the average energy density of the electric field will be

Option: 1

 35.2 x 10-10 J/m3


Option: 2

 35.2 x 10-11 J/m3


Option: 3

 35.2 x 10-12 J/m3


Option: 4

 35.2 x 10-13 J/m3


Answers (1)

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\\ \text{Energy density is given as:} \\ \mathrm{e}=\frac{\mathrm{\epsilon}_0 \mathrm{E}^2}{2}=8.8 \times 10^{-12} \times 8=70.4 \times 10^{-12} \frac{\mathrm{J}}{\mathrm{m}^3} \\ \\ \text{Therefore, average energy density} =\mathrm{e} / 2=35.2 \times 10^{-12} \mathrm{~J} / \mathrm{m}^3

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Ritika Jonwal

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