Get Answers to all your Questions

header-bg qa

 An Electron  (mass =9.1 \times 10^{-31}; charge =-1.6 \times 10^{-19} \mathrm{c})  experiences no deflection if subjected to an magnetic field of  2.0 \times 10^{-3} \,\mathrm{wb} / \mathrm{m}^2 and an electric field of  3.2 \times 10^5 \,\mathrm{v/m}. Both the fields are normal to the path of the electrons and to each other. if the electric field is removed then the electron Will revolve in an orbit of radius:


 

Option: 1

45 m


Option: 2

4.5 m


Option: 3

0.45 m


Option: 4

0.045 m


Answers (1)

best_answer

q V B =q E \\
\Rightarrow V B =E \,\,\,\,\,\,\,\Rightarrow V= \frac{E}{B} \\
\text { and }, R =\frac{m v}{q B} \\
                 =\frac{m \times E}{B \times q B} \\
                =\frac{9.1 \times 10^{-31} \times 3.2 \times 10^5}{\left(2 \times 10^{-3}\right)^2 \times 1.6 \times 10^{-19}} \\
                =0 .45 \mathrm{~m}

Posted by

Ritika Jonwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE