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An electron is constrained to move along the y-axis with a speed of 0.1\; c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is \vec{E}=30\; \hat{j}\sin (1.5\times 10^{7}t-5\times 10^{-2}x)V/m. The maximum magnetic force experienced by the electron will be : (given c=3\times 10^{8}ms^{-1} and electron charge =1.6\times 10^{-19}C )
Option: 1 3.2\times 10^{-18}N  
Option: 2 2.4\times 10^{-18}N
Option: 3 4.8\times 10^{-19}N
Option: 4 1.6\times 10^{-19}N

Answers (1)

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\begin{array}{l} \Rightarrow \mathrm{E}=\overrightarrow{\mathrm{E}}=30 \hat{\mathrm{j}} \sin \left(1.5 \times 10^{7} \mathrm{t}-5 \times 10^{-2} \mathrm{x}\right) \mathrm{V} / \mathrm{m} \\ \Rightarrow \mathrm{B} \Rightarrow \mathrm{E} / \mathrm{V} \Rightarrow \frac{30}{1.5 \times 10^{7}} \times 5 \times 10^{-2} \\ \Rightarrow 10^{-7} \text {Tesla } \\ \Rightarrow \mathrm{F}_{\mathrm{mag}}=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})=|\mathrm{qVB}| \\ =1.6 \times 10^{-19} \times 0.1 \times 3 \times 10^{8} \times 10^{-7} \\ =4.8 \times 10^{-19} \mathrm{~N} \end{array}

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Deependra Verma

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