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An Electron is Projected with velocity  V0 in a uniform electric field E perpendicular to the field. Again it is Projected with velocity V0 Perpendicular to a uniform magnetic field  B. If  r1 is the initial radius of curvature Just after entering in the Electric field and r2 is initial radius of curvature Just after entering in magnetic field then the ratio  r1 / r2  is 

 

Option: 1

\frac{B V_0^2}{E}


Option: 2

\frac{B }{E}


Option: 3

\frac{E V_0}{B}


Option: 4

\frac{B V_0}{E}


Answers (1)

best_answer

q E=\frac{m V_0^2}{r_1} \\

q V_0 B=\frac{m V_0^2}{r_2} \\

r_1=\frac{m V_0^2}{q E}

r_2=\frac{m V_0}{q B}

\quad \frac{r_1}{r_2}=\frac{B V_0}{E} \\

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