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An electron of mass \mathrm{m}, charge \mathrm{e} falls through \mathrm{a} distance h meter in a uniform electric field \mathrm{E}. Then time of fall?

Option: 1

 \mathrm{t=\sqrt{\frac{2 h m}{e E}}}


Option: 2

\mathrm{ t=\frac{2 h m}{e E} }


Option: 3

\mathrm{t=\sqrt{\frac{2 e E}{h m}} }


Option: 4

\mathrm{t=\frac{2 e E}{\mathrm{hm}}}


Answers (1)

best_answer

use newtons equation of motion -

\mathrm{s=u t+\frac{1}{2}at^{t}} 


\mathrm{s=0+\frac{1}{2} \frac{e E}{m} \cdot t^2}                          \mathrm{e E=m a }


\mathrm{s=\frac{e E}{2 m} t^2 }


\mathrm{t^2=\frac{h 2 m}{e E} }

t=\sqrt{\frac{2hm}{eE}}
 
 

Posted by

jitender.kumar

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