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  • An electron (of mass m) & a photon have the same energy E. Find the ratio of de Broglie wavelength of an electron and the wavelength of the photon (c = speed of light in vacuum).  Option: 1

An electron (of mass m) & a photon have the same energy E. Find the ratio of de Broglie wavelength of an electron and the wavelength of the photon (c = speed of light in vacuum).  
Option: 1  \left ( \frac{E}{2m} \right )^{1/2} 
Option: 2   \frac{1}{c}\left ( \frac{2E}{m} \right )^{1/2}

Option: 3  c\left ( 2mE \right )^{1/2} 
Option: 4  \frac{1}{c}\left ( \frac{E}{2m} \right )^{1/2}
 

Answers (1)

best_answer

 

 

 

\lambda_{\mathrm{d}}$ for electron $=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}} \\ \lambda$ for photon $=\frac{\mathrm{hC}}{\mathrm{E}}$ \\ Ratio $=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}}\times \frac{\mathrm{E}}{\mathrm{hC}}=\frac{1}{\mathrm{C}} \sqrt{\frac{\mathrm{E}}{2 \mathrm{m}}}

Hence the correct option is (4).  

Posted by

Ritika Jonwal

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