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An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)
 
Option: 1 \frac{1}{c}\left ( \frac{E}{2m} \right )^{\frac{1}{2}}
Option: 2 c\left ( 2mE \right )^{\frac{1}{2}}
Option: 3 \left ( \frac{E}{2m} \right )^{\frac{1}{2}}  
Option: 4 \frac{1}{c}\left ( \frac{2m}{E} \right )^{\frac{1}{2}}

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\begin{array}{l} \lambda_{1}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}} \\ \\ \lambda_{2}=\frac{\mathrm{hc}}{\mathrm{E}} \\ \\ \frac{\lambda_{1}}{\lambda_{2}}=\frac{1}{\mathrm{c}}\left(\frac{\mathrm{E}}{2 \mathrm{~m}}\right)^{1 / 2} \end{array}

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