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  • An element crystallites  in a face centered cubic (fcc) unit cell with cell edge a. The distance between the centre of two nearest octahedral voids in the crystal lattice is:Option: 1 <img alt="\sqrt{2a}" src="https://learn.careers360.com

An element crystallites  in a face centered cubic (fcc) unit cell with cell edge a. The distance between the centre of two nearest octahedral voids in the crystal lattice is:
Option: 1 \sqrt{2a}
Option: 2 \frac{a}{2}
Option: 3 \frac{a}{\sqrt{2}}
Option: 4 a

Answers (1)

best_answer

The octahedral void is at the middle of the edge in FCC.

The equation is given as:

\mathrm{x\: =\: \sqrt{\left ( \frac{a}{2} \right )^{2}\: +\: \left ( \frac{a}{2} \right )^{2}}\: =\: \frac{a}{\sqrt{2}}}

Therefore, Option(3) is correct.

Posted by

Kuldeep Maurya

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