An element with atomic number 82 belongs to which group of the long form of the periodic table?
14
16
12
10
How to find Group, Periods and Blocks of any element -
Now, its last electron enters into the s-subshell, therefore, Na belongs to the s-block.
Group
The group of any element is determined in different ways.
For s-block
If the last electron of any element enters into the s-subshell, then the group number is equal to the number of electrons in the last s-subshell.
For example, K has atomic number 19, thus its electronic configuration can be written as:
1s22s22p63s23p64s1
Now it has 1 electron in the s-subshell, therefore K belongs to Group 1.
For p-block
If the last electron of any element enters into the p-subshell, then the group number is equal to (12 + the number of electrons in the last p-subshell).
For example, Ge has atomic number 32, thus its electronic configuration can be written as:
1s22s22p63s23p64s23d104p2
Now, it has 2 electrons in the last p-subshell, therefore its group number is:
12 + 2 = 14
Thus, Ge belongs to Group 14
If the last electron of any element enters into the d-subshell, then the group number is equal to (2 + the number of electrons in (n-1)d-subshell.
For example, Mn has atomic number 25, thus its electronic configuration can be written as:
1s22s22p63s23p64s23d5
Now it has 5 electrons in the d-subshell, therefore its group number is:
2 + 5 = 7
Thus, Mn belongs to Group 7.
There are only two series of f-block i.e, lanthanide and actinide. If the last electron of any element enters into the f-subshell and if the atomic number is between 57-71, then the element belongs to lanthanide series i.e, 6th period. Further, if the last electron of any element enters into the f-subshell and if the atomic number is between 89-103, then the element belongs to the actinide series i.e, 7th period. All the elements from both these series belong to group 3.
-
To find the group number for a particular element, first, we should know the electronic configuration of that element. The electronic configuration of an element with atomic number 82 is:
[Xe] 4f14 5d10 6s2 6p2
We can see from the electronic configuration that the last electron enters in p-subshell
Therefore group number is = 12+2 = 14 electrons.
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