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  • An empty LPG cylinder weighs . When full, it weighs <img alt="29.0 \mathrm{~kg}" src="https://entrancecorner.codecogs.com/gif.latex?29.0%20%5Cma

An empty LPG cylinder weighs 14.8 \mathrm{~kg}. When full, it weighs 29.0 \mathrm{~kg} and shows a pressure of 3.47 \mathrm{~atm}. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 \mathrm{~kg}. The final pressure inside the cylinder is __________\mathrm{atm}. (Nearest integer) (Assume LPG to be an ideal gas)
 

Answers (1)

best_answer

$Mass of LPG $= (29-14.8)\ kg = 14.2\ kg

Now, for full cylinder,

\mathrm{PV = nRT}

\mathrm{\Rightarrow 3.47 \ V= \frac{14. 2}{M}\times RT}

\mathrm{\Rightarrow M= \frac{14. 2RT}{3. 47V} \quad\quad \quad... eqn(i)}

Next,

When weight of Cylinder is reduced to \mathrm{23\ kg}, then mass of  \mathrm{LPG= 8. 2\ kg}

Applying the ideal gas equation,

\mathrm{ PV= nRT}

\mathrm{\Rightarrow P\times V= \frac{8. 2}{M}RT}

Putting value of M from \mathrm{ eqn(i)}, we have 

\begin{aligned}\text{P} &=\frac{8 . 2 \times 3 . 47 \times \text{V} \times \text{R T}}{14 . 2 \text{~RTV}} \\ &=\frac{8 .2 \times 3 . 47}{14 . 2} \\ &=2\ \text{atm} \end{aligned}

Hence, the answer is 2

Posted by

sudhir.kumar

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