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  • An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2 . Given that a student has failed in Paper 2. the probability of

An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2 . Given that a student has failed in Paper 2. the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers is

Option: 1

0.5


Option: 2

0.18


Option: 3

0.12


Option: 4

0.06


Answers (1)

best_answer

Let A and B be events of failing in paper 1 and paper 2 respectively.

          \begin{aligned} \text{P(A)} & =0.3 \\ \\\text{P(B)} & =0.2 \\ \\\mathrm{P(\frac{A}{B}) }& =0.6 \end{aligned}

Required Probability

                       \begin{aligned} & \mathrm{=P(A \cap B)} \\ \\& =\mathrm{P(A \mid B) P(B)} \\ \\& =0.6 \times 0.2 \\ \\& =0.12 \end{aligned}

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