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  • An experiment is conducted to determine the acceleration due to gravity  using a simple pendulum. The length of t

An experiment is conducted to determine the acceleration due to gravity (g) using a simple pendulum. The length of the pendulum is L=1.2\ m, and the time period of one oscillation is T=2\ s. Calculate the acceleration due to gravity.

Option: 1

2.415\ m/s^2


Option: 2

3.728\ m/s^2


Option: 3

4.521\ m/s^2


Option: 4

6.225\ m/s^2


Answers (1)

Given values:
• Length of pendulum (L)=1.2\ m
• Time period (T)=2\ s
The acceleration due to gravity (g) can be calculated using the formula for
the time period of a simple pendulum:
T=2 \pi \sqrt{\frac{L}{g}}

Solve for g:

g=\frac{4 \pi^2 L}{T^2}

Step 1: Substitute the given values and calculate the acceleration due to
gravity (g):

g=\frac{4 \pi^2 \times 1.2 \mathrm{~m}}{(2 \mathrm{~s})^2}

Step 2: Calculate g:

\begin{gathered} g=\frac{14.913 \mathrm{~m}^2 / \mathrm{s}}{4 \mathrm{~s}^2} \\ g \approx 3.728 \mathrm{~m} / \mathrm{s}^2 \end{gathered}

The acceleration due to gravity is approximately 3.728\ m/s^2.
.Conclusion
The acceleration due to gravity is calculated to be approximately 3.728\ m/s^2.
.Therefore, the correct option is (B).

Posted by

Kshitij

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