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An experiment is conducted to measure the thickness of a thin sheet using a screw gauge. The main scale reading is 2 mm, and the circular scale reading is 25. The pitch of the screw gauge is 0.5 mm, and the least count of the instrument is 0.01 mm. Determine the thickness of the thin sheet.

Option: 1

1.125 mm


Option: 2

2.00 mm


Option: 3

11.25 mm


Option: 4

112.5 mm


Answers (1)

best_answer

Given values:

Main scale reading (M) = 2 mm
Circular scale reading (C) = 25
Pitch of the screw gauge (P) = 0.5 mm
Least count (LC) = 0.01 mm

The total reading of the screw gauge can be calculated by adding the main scale reading to the product of the circular scale reading and the least count:

                    Total reading = M + (C * LC)

Step 1: Calculate the total reading of the screw gauge:

                    Total reading = 2 mm + (25 * 0.01 mm) = 2 mm + 0.25 mm = 2.25 mm

The thickness of the thin sheet can be calculated using the formula:

                    Thickness = Total reading * P

Step 2: Calculate the thickness:

                    Thickness = 2.25 mm * 0.5 mm = 1.125 mm

The thickness of the thin sheet is 1.125 mm.

Posted by

Kuldeep Maurya

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