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  • An ideal transformer with purely resistive load operates at 12 kV on the primary side. It supplies electrical energy to a number of nearby houses at 120 V. The average rate of energy consump

An ideal transformer with purely resistive load operates at 12 kV on the primary side. It supplies electrical energy
to a number of nearby houses at 120 V. The average rate of energy consumption in the houses served by the
transformer is 60 kW. The value of resistive load (Rs) required in the secondary circuit will be ________ m\Omega.

Option: 1

240


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \frac{V_s}{V_p}=\frac{N_s}{N_p} \\ & \Rightarrow \frac{120}{12000}=\frac{N_s}{N_p} \\ & \Rightarrow \frac{N_s}{N_p}=\frac{1}{100}---(i) \end{aligned}

For an ideal transformer, input power = Output power
And power is given by P=i V
\begin{aligned} & i_p V_p=i_s V_s=60000 \mathrm{~W} \\ & i_p=\frac{60000}{12000}=5 \end{aligned}
Now, R_p=\frac{V_p}{i_p}=\frac{12000}{5}=2400 \Omega
R_s=\frac{V_s}{i_s}=\frac{120}{60000 / 120}=120 \times \frac{120}{60000}=\frac{120}{500}=0.240 \Omega=240 \mathrm{~m} \Omega
 

Posted by

shivangi.bhatnagar

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