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An isotope of In has very short half-life period of 10 \mathrm{~min}, its decay constant and average life are respectively:

Option: 1

6.93 \times 10^{-2} \mathrm{~min}^{-1}, 18.4 \mathrm{~min}


Option: 2

6.93 \times 10^{-4} \mathrm{~min}^{-1}, 14.43 \mathrm{~min}


Option: 3

6.93 \times 10^{-2} \mathrm{~min}^{-1}, 14.43 \mathrm{~min}


Option: 4

6.93 \times 10^{-4} \mathrm{~min}^{-1}, 18.4 \mathrm{~min}


Answers (1)

best_answer

\mathrm{\lambda=\frac{0.693}{t_{1 / 2}}}
\mathrm{\lambda=\frac{0.693}{10} }
\mathrm{\lambda=693 \times 10^{-4} \mathrm{~min}^{-1} }

\mathrm{\tau=\frac{1}{\lambda}=\frac{10000}{693}=14.43 \mathrm{~min} }

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