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An LCR circuit contains resistance of 110 \Omega and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45°. If on the other hand, only inductor is removed the current leads by 45° with the applied voltage. The rms current flowing in the circuit will be :
 
Option: 1 1 A
Option: 2 2.5 A
Option: 3 1.5 A  
Option: 4 2 A

Answers (1)

best_answer

According to the given question

\\ \tan 45^{\circ}=\frac{X_C}{R}=\frac{1}{\omega C R} \\\\ \tan 45^{\circ} =\frac{X_L}{R}=\frac{\omega L}{R} \\\\ \Rightarrow X_{L}=X_{C}

So this satisfies the condition of resonance.

So

\begin{array}{l} \mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}} =\frac{220}{110}=2 \mathrm{~A} \end{array}

Posted by

Deependra Verma

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