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An LCR series circuit of capacitance 62.5 \mathrm{nF} and resistance of 50 \Omega,is connected to an A.C. source of frequency 2.0 \mathrm{kHz} For maximum value of amplitude of current in circuit, the value of inductance is _______ mH.\text { Take } \pi^2=10 \text { ) }

Option: 1

100


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

At maximum current, there will be condition of resonance.
   \begin{aligned} & \text { So, } \omega=\frac{1}{\sqrt{L C}} \\ & \Rightarrow L=\frac{1}{\omega^2 C}=\frac{1}{4 \times \pi^2 \times 4 \times 10^6 \times 62.5 \times 10^{-9}} H=0.1 \mathrm{H}=100 \mathrm{mH} \end{aligned}

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Divya Prakash Singh

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