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  • An n.p.n transistor with current gain in common emitter configuration is shown in figure. The output volt

An n.p.n transistor with current gain \beta=100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be

Option: 1

0.1 \mathrm{~V}


Option: 2

1.0 \mathrm{~V}


Option: 3

10 \mathrm{~V}


Option: 4

100 \mathrm{~V}


Answers (1)

best_answer

\mathrm{\Delta V_i =\Delta I_B R_B }

\mathrm{I_{m V} =\Delta I_B \times 1000 }

\mathrm{\Delta I_B =10^{-6} A }

\mathrm{B =100=\frac{\Delta I_C}{\Delta I_B} ; \Delta I_C=10^{-4} \mathrm{~A}}

The output voltage of the amplifier is

\mathrm{\Delta V_{o}=\Delta I_{c}R_{c}=10^{-4}\times 10^{4}}

                            \mathrm{=1V}

Hence 2 is correct option





 

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