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  • An object AB is placed on the axis of a concave mirror of a focal length 10cm. End A of the object is at 30cm from the mirror. If the length of an object is 1mm, then length of its image

An object AB is placed on the axis of a concave mirror of a focal length 10cm. End A of the object is at 30cm from the mirror. If the length of an object is 1mm, then length of its image is?

Option: 1

0.25 mm


Option: 2

0.50mm


Option: 3

1mm


Option: 4

1.50mm


Answers (1)

best_answer

As we learn

Longitudinal magnification -

m= \frac{-v^{2}}{u^{2}}

- wherein

Longitudinal magnification is used when object is placed along principal axis.   

u = object distance

v = image distance

 

 u = -30cm , f = -10cm

\Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{u}=\frac{1}{-10}+\frac{1}{30}=-\frac{1}{15}

\therefore v = -15cm

 dv = \large = -\frac{v^{2}}{u^{2}} .du    \large = -\frac{(-15)^{2}}{(-30)^{2}}\large = -\frac{(-15)^{2}}{(-30)^{2}} \cdot 1mm

=0.25mm

 

Posted by

Devendra Khairwa

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