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An observer can see through a pinhole the top end of a thin rod of height h, placed as shown in the figure.  The beaker height is 3h and its radius h.  When the beaker is filled with a liquid up to a height of 2h, he can see the lower end of the rod.  Then the refractive index of the liquid is 

Option: 1

5/2                                           


Option: 2

\sqrt\frac{5}{2}


Option: 3

\sqrt\frac{3}{2}


Option: 4

\frac{3}{2}


Answers (1)

best_answer

 

 

The line of sight of the observer remains constant, making an angle of 45° with the normal.

\sin \theta=\frac{h}{\sqrt{h^{2}+(2 h)^{2}}}=\frac{1}{\sqrt{5}}

\mu=\frac{\sin 45^{\circ}}{\sin \theta} \quad=\frac{1 / \sqrt{2}}{1 / \sqrt{5}}=\sqrt{\left(\frac{5}{2}\right)}

 

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sudhir.kumar

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