# An open vessel at 270 C is heated until two fifth of the air (assumed as an ideal gas ) in it has escaped from the vessel. Assuming that the volume of  the vessel remains constant, the temperature at which the vessel has been heated is :

Ideal Gas Law in terms of density -

$PM=d RT$

- wherein

where

d - density of gas

P - Pressure

R - Gas Constant

T - Temperature

M - Molar Mass

Saturated Vapour Pressure -

When equilibrium is attained between vapor and liquid kept in a partially filled beaker, the vapor pressure at that temperature is called saturated vapor pressure.

As we have learned in the gaseous state

we know $\frac{2}{5}$ air escaped for vessel,$\therefore \frac{3}{5}$ air reamain

in vessel.

P,V constant

$n_{1}T_{1}=n_{2}T_{2}$

$n_{1}\left ( 300 \right )=\left ( \frac{3}{5}n _{1} \right )T_{2}\Rightarrow T_{2}=500K$

### Preparation Products

##### JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
##### Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
##### Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
##### Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-