Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

An oscillating LC circuit consists of a 75 mH inductor and a 1.2\mu F capacitor. If the maximum charge to the capacitor is 2.7\mu C. The maximum current in the circuit will be __________ mA .

Option: 1

9


Option: 2

____


Option: 3

____


Option: 4

____


Answers (1)

best_answer

LC oscillation L = 75mH
\begin{aligned} & \mathrm{C}=1.2 \mu \mathrm{F} \\ & \mathrm{U}_{\max \mathrm{L}}=\mathrm{U}_{\max \mathrm{C}} \\ & \frac{1}{2} \mathrm{LI}_{\max }^2=\frac{1}{2} \frac{\mathrm{q}_{\max }^2}{\mathrm{C}} \\ & \mathrm{I}_{\max }=\frac{\mathrm{q}_{\max }}{\sqrt{\mathrm{LC}}} \Rightarrow \mathrm{I}_{\max }=\frac{2.7 \times 10^{-6}}{\sqrt{75 \times 10^{-3} \times 1.2 \times 10^{-6}}} \\ & \mathrm{I}_{\max }=9 \times 10^{-3} \mathrm{~A} \\ & \mathrm{I}_{\max }=9 \mathrm{~mA} \end{aligned}

Posted by

Gautam harsolia

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Results LIVE: NTA April session result date, time soon; BTech scorecard at jeemain.nta.nic.in
anam-khan

JEE Main 2025 answer key is provisional: NTA says 'drawing conclusions not desirable'
anam-khan

'Students pay for NTA’s mistakes': JEE Main 2025 answer key shows 9 errors, out-of-syllabus questions

Latest Question