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Angle between the tangents to the curve  y=x^{2}-5x+6 at the points \left ( 2,0 \right ) and \left ( 3,0 \right ) is

Option: 1

\frac{\pi }{2}


Option: 2

\frac{\pi }{3}


Option: 3

\frac{\pi }{6}


Option: 4

\frac{\pi }{4}


Answers (1)

best_answer

Use the concept 

y= x^2 -5x+6

\frac{dy}{dx}= 2x -5

m_1 = -1

m_2 = 1

m_1 \times m_2 =-1

\therefore 90^{\circ}

Posted by

chirag

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