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A coil of cross-sectional area A having n turns is placed in a uniform magnetic field
B. When it is rotated with an angular velocity ω, the maximum e.m.f. induced
in the coil will be :

  • Option 1)

    3 nBAω

  • Option 2)

    3/2 nBAω

  • Option 3)

     nBAω

  • Option 4)

    1/2 nBAω

 

Answers (2)

best_answer

As we have learned

If Angle θ — change -

\varepsilon = -NABd\frac{\left ( \cos \Theta \right )}{d\Theta }\times \frac{d\Theta }{dt}

\varepsilon =+NBA\; \omega \sin \Theta

 

-

 

emf induced is e = (NBA\omega\cos wt

maximum value of e is NBA\omega

 

 

 

 

 


Option 1)

3 nBAω

This is incorrect

Option 2)

3/2 nBAω

This is incorrect

Option 3)

 nBAω

This is correct

Option 4)

1/2 nBAω

This is incorrect

Posted by

prateek

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