A photon of wavelength 6000 Å has an energy E. The wavelength of the photon of light which corresponds to an energy equal to 2E is Option 1) 300 Å Option 2) 3000 Å Option 3) 30 Å Option 4) 3 Å

As learnt

The energy (E) of a quantum of radiation -

Where h is plank’s constant and  is frequency

-

AND

Speed of electromagnetic radiation -

where frequency is (,pronounced as nu), wavelength is (λ) and velocity of light is(c)

-

We know,

E= energy of a quantum of radiation

h=plank's constant

and

Now,

Put in 2

Option 1)

300 Å

Option is incorrect

Option 2)

3000 Å

Option is correct

Option 3)

30 Å

Option is incorrect

Option 4)

3 Å

Option is incorrect

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