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  • Answer please! A solid sphere, a hollow sphere and a ring are released from top of an inclined plane ( (frictionless ) so that they slide down the plane . Then maximum acceleration down the plane is for ( no rolling )

A solid sphere, a hollow sphere and a ring are released from top of an inclined plane ( (frictionless ) so that they slide down the plane . Then maximum acceleration down the plane is for ( no rolling )

Option 1)

Solid sphere

 Option 2)

hollow sphere
Option 3)

ring

 Option 4)

all same

Answers (3)

best_answer

As we learnt in

Rolling of a body on an inclined plane -

a= \frac{g\sin \Theta }{1+\frac{K^{2}}{R^{2}}}

f= \frac{mg\sin \Theta }{1+\frac{R^{2}}{K^{2}}}

- wherein

K=Radius of gyration

\Theta = Angle of inclination

 

 

 This is the case of sliding (the plane being frictionless) therefore the acceleration of all the bodies is same a=g \;sin\theta


Option 1)

Solid sphere

This is an incorrect option.

Option 2)

hollow sphere

This is an incorrect option.

Option 3)

ring

This is an incorrect option.

Option 4)

all same

This is the correct option.

Posted by

perimeter

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Solid sphere

Posted by

balasubramanian

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I think the answer should be a ring

 

 

 

 

Posted by

Pihu Dandapat

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