A solid sphere, a hollow sphere and a ring are released from top of an inclined plane ( (frictionless ) so that they slide down the plane . Then maximum acceleration down the plane is for ( no rolling )

Option 1)

Solid sphere

Option 2)

hollow sphere

Option 3)

ring

Option 4)

all same

Answers (3)

As we learnt in

Rolling of a body on an inclined plane -

a= \frac{g\sin \Theta }{1+\frac{K^{2}}{R^{2}}}

f= \frac{mg\sin \Theta }{1+\frac{R^{2}}{K^{2}}}

- wherein

K=Radius of gyration

\Theta = Angle of inclination

 

 

 This is the case of sliding (the plane being frictionless) therefore the acceleration of all the bodies is same a=g \;sin\theta


Option 1)

Solid sphere

This is an incorrect option.

Option 2)

hollow sphere

This is an incorrect option.

Option 3)

ring

This is an incorrect option.

Option 4)

all same

This is the correct option.

Solid sphere

I think the answer should be a ring

 

 

 

 

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