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  • Answer please! At room temperature the r.m.s. velocity of the molecules of a certain diatomic gas is found to be 1930 m/sec. The gas is

At room temperature the r.m.s. velocity of the molecules of a certain diatomic gas is found to be 1930 m/sec. The gas is

  • Option 1)

    H_2

  • Option 2)

    F_2

  • Option 3)

    O_2

  • Option 4)

    Cl_2

 

Answers (1)

best_answer

As we learnt in 

Root mean square velocity -

V_{rms}= \sqrt{\frac{3RT}{M}}

= \sqrt{\frac{3P}{\rho }}
 

- wherein

R = Universal gas constant

M = molar mass

P = pressure due to gas

\rho = density

 

 V_{rms}=\sqrt{\frac{3RT}{M}}\ \: \: \: or\ \: \: \: M=\frac{3RT}{V^{2}_{rms}}

or\ \: \: M= \frac{3 \times 8.31 \times 300}{(1930)^{2}} \times 1000 g \simeq 2g

\therefore    Molecule is H2.

 

 


Option 1)

H_2

Correct

Option 2)

F_2

Incorrect

Option 3)

O_2

Incorrect

Option 4)

Cl_2

Incorrect

Posted by

divya.saini

View full answer

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