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  2. Answer please! - Atomic Structure - JEE Main-2
# Engineering

The graph between \left | \psi \right |^{2} and  r ( radial distance ) is shown below.

This represents :

  • Option 1)

    3s orbital

  • Option 2)

    2s orbital

  • Option 3)

    1s orbital

  • Option 4)

    2p orbital

Answers (1)
S solutionqc

For 's' , graph always starts from above.

For every other orbital, graph starts from origin.

\therefore this graph is for 's'-orbital.

=> Thus , l=0

=> In this graph, only one radial node is present ( point A).

We know that, radial node is given by (n-l-1)

\therefore n-l-1 = 1( as only one radial node is present)

n-1 = 1 ( \because l = 0)

=> n = 2

\therefore graph is for 2s

So, option (2) is correct.


Option 1)

3s orbital

Option 2)

2s orbital

Option 3)

1s orbital

Option 4)

2p orbital

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