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Answer please! - Chemical Bonding and Molecular Structure - JEE Main

During the change of O_{2} to O_{2}^{-}, the incoming electron goes to the orbital :

 

  • Option 1)

    \pi 2 p_{y}

  • Option 2)

    \sigma ^{*}2p_{z}

  • Option 3)

    \pi^{*}2p_{x}

  • Option 4)

    \pi 2 p_{x}

Answers (1)
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S solutionqc

For O_{2} molecule , the molecule orbital sequence  follows the given order :

\sigma 1 s^{2} \sigma^{*} 1 s^{2} \sigma 2 s^{2} \sigma^{*} 2 s^{2} \sigma 2 p_{z}^{2} \pi 2 p_{x}^{2} = \pi 2 p_{y}^{2}  \pi^{*} 2 p_{x}^{1} = \pi^{*} 2 p_{y}^{1}

Now, from O_{2} to O_{2}^{-} , the incoming electron will go into (\pi^{*}2p_{z}) orbital and thus 

the final sequence will be 

\sigma 1 s^{2} \sigma^{*} 1 s^{2} \sigma 2 s^{2} \sigma^{*} 2 s^{2} \sigma 2 p_{z}^{2} \pi 2 p_{x}^{2} = \pi 2 p_{y}^{2}  \pi^{*} 2 p_{x}^{1} = \pi^{*} 2 p_{y}^{1}

\therefore option (3) is correct.


Option 1)

\pi 2 p_{y}

Option 2)

\sigma ^{*}2p_{z}

Option 3)

\pi^{*}2p_{x}

Option 4)

\pi 2 p_{x}

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