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During the change of $O_{2}$ to $O_{2}^{-}$ , the incoming electron goes to the orbital :

Option 1)
$\pi 2 p_{y}$
Option 2)
$\sigma ^{}2p_{z}$
Option 3)
$\pi^{}2p_{x}$
Option 4)
$\pi 2 p_{x}$

Answers (1)

best_answer

For $O_{2}$ molecule , the molecule orbital sequence follows the given order :

$\sigma 1 s^{2}$ $\sigma^{*} 1 s^{2}$ $\sigma 2 s^{2}$ $\sigma^{*} 2 s^{2}$ $\sigma 2 p_{z}^{2}$ $\pi 2 p_{x}^{2}$ = $\pi 2 p_{y}^{2}$ $\pi^{*} 2 p_{x}^{1}$ = $\pi^{*} 2 p_{y}^{1}$

Now, from $O_{2}$ to $O_{2}^{-}$ , the incoming electron will go into ( $\pi^{*}2p_{z}$ ) orbital and thus

the final sequence will be

$\sigma 1 s^{2}$ $\sigma^{*} 1 s^{2}$ $\sigma 2 s^{2}$ $\sigma^{*} 2 s^{2}$ $\sigma 2 p_{z}^{2}$ $\pi 2 p_{x}^{2}$ = $\pi 2 p_{y}^{2}$ $\pi^{*} 2 p_{x}^{1}$ = $\pi^{*} 2 p_{y}^{1}$

$\therefore$ option (3) is correct.

Option 1)

$\pi 2 p_{y}$

Option 2)

$\sigma ^{*}2p_{z}$

Option 3)
$\pi^{*}2p_{x}$
Option 4)

$\pi 2 p_{x}$

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