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# Answer please! - Chemical Kinetics and Surface Chemistry - BITSAT

For adsorption of a gas on a solid, the plot of log $\frac{x}{m}$ Vs log p is linear with slope equal to

• Option 1)

K

• Option 2)

log K

• Option 3)

n

• Option 4)

$\frac{1}{n}$

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As we learned inc oncept

Logarithmic graph of Freundlich isotherm -

$log\frac{x}{m}= log K+\frac{1}{n}log p$

- wherein

The slope of the straight line gives the value of 1/n. The intercept on y-axis gives the value of log K.

According to Treundlich adsorption,

Isotherm, $\frac{x}{m}= Kp^{\frac{1}{n}}$

$D \log \frac{x}{m}= \log K +\frac{1}{n}\ log p$

Plotting the above equation in graph, we get

The slope gives the value of 1/x

Option 1)

K

Incorrect option

Option 2)

log K

Incorrect option

Option 3)

n

Incorrect option

Option 4)

$\frac{1}{n}$

Correct option

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