If one of the lines of  my^{2}+(1-m^{2})xy-mx^{2}=0 is a bisector of the angle between the lines xy=0,\; \; then \; \; m\; \; is

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    –1/2

  • Option 4)

    –2

 

Answers (1)

As we learnt in 

 

Slope of a line -

If \Theta is the angle at which a straight line is inclined to a positive direction of x-axis, then the slope is defined by

m= \tan \Theta.

- wherein

 

 my^{2}+(1-m)^{2}xy-mx^{2}=0

y(my+x)-mx(my+x)=0

(y-mx)(my+x)=0

xy=0\:\:\:\:is\ x=0 \:\:\:\:and\:\:\:\:y=0

So slope of line equally inclined is:

\Theta= \frac{\pi}{4}

\tan \Theta=1


Option 1)

1

This option is correct.

Option 2)

2

This option is incorrect.

Option 3)

–1/2

This option is incorrect.

Option 4)

–2

This option is incorrect.

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