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  • Answer please! - Complex numbers and quadratic equations - JEE Main-5

Let  z_{1}  and  z_{2}  are complex numbers such that \left | z_{1}z_{2} \right |=4. If  a= \left |z_{1} \right |^{2} and   b= \left |z_{2} \right |^{2}  then ab equals

  • Option 1)

    4

  • Option 2)

    8

  • Option 3)

    16

  • Option 4)

    32

 

Answers (1)

best_answer

ab=\left | z_{1} \right |^{2}\left | z_{2} \right |^{2}=\left ( \left | z_{1} \right |\cdot \left | z_{2} \right | \right )^{2}=\left | z_{1}z_{2} \right |^{2}=4^{2}=16

\therefore Option (C)

 

Property of Modulus of z(Complex Number) -

|z1z2|=|z1||z2|

- wherein

|.| denotes modulus of complex number

 

 


Option 1)

4

This is incorrect

Option 2)

8

This is incorrect

Option 3)

16

This is correct

Option 4)

32

This is incorrect

Posted by

divya.saini

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