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Answer please! - d - and f - BLOCK ELEMENTS - JEE Main

Thermal decomposition of an Mn compound (X) at 513 results in a compound Y, MnO_{2} and a gaseous product. MnO_{2} reacts with NaCI and concentrated H_{2}SO_{4} to give a pungent gas Z. X, Y, and Z, respectively, are:

 

  • Option 1)

    K_{3}MnO_{4},K_{2}MnO_{4} and Cl_{2}

     

     

     

  • Option 2)

    K_{2}MnO_{4}, KMnO_{4} and SO_{2}

  • Option 3)

    KMnO_{4}, K_{2}MnO_{4} and Cl_{2}

  • Option 4)

    K_{2}MnO_{4}, KMnO_{4} and Cl_{2}

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\begin{matrix} 2KMno_{4}\\(x) \end{matrix}\xrightarrow[\Delta ]{513k}\begin{matrix} K_{2}MnO_{4} \\ (y) \end{matrix}+MnO_{2} + O_{2(g)}

MnO_{2}+4NaCl+4H_{2}SO_{4}\rightarrow MnCl_{2}+4NaHSO_{4}+2H_{2}O+\begin{matrix} \\\ Cl_{2}(g) \\ z \end{matrix}

\left [ \begin{matrix} x=KMnO_{4} \\ y=K_{2}MnO_{4} \\ z=Cl_{2} \end{matrix}\right ]


Option 1)

K_{3}MnO_{4},K_{2}MnO_{4} and Cl_{2}

 

 

 

Option 2)

K_{2}MnO_{4}, KMnO_{4} and SO_{2}

Option 3)

KMnO_{4}, K_{2}MnO_{4} and Cl_{2}

Option 4)

K_{2}MnO_{4}, KMnO_{4} and Cl_{2}

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