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header-bg qa

In the circuit shown in figure, find the current through the branch BD

  • Option 1)

    5A

  • Option 2)

    0A

  • Option 3)

    3A

  • Option 4)

    4A

 

Answers (1)

best_answer

As we have learnt,

 

Kirchhoff's Law -

\sum q=0

-

 

 

 

The current in the circuit are assumed as shown in the fig.

Applying KVL along the loop ABDA, we get

6i1 – 3 i2 + 15 = 0 or 2i1 + i2 = 5 …..(i)

Applying KVL along the loop BCDB, we get

3(i1i2) – 30 + 3i2 = 0 or i1 + 2i2 = 10 …..(ii)

Solving equation (i) and (ii) for i2, we get i2 = 5 A.


Option 1)

5A

Option 2)

0A

Option 3)

3A

Option 4)

4A

Posted by

Avinash

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