A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad s-1, the magnitude of its angular momentum about a point on the ground right under the centre of the circle is :
Option 1)
8.64 kg m2s-1 |
Option 2)
11.52 kg m2s-1
|
Option 3)
14.4 kg m2s-1 |
Option 4)
20.16 kg m2s-1 |
As we learnt
Angular momentum -
- wherein
represent angular momentum of a moving particle about a point.
it can be calculated as
= Length of perpendicular on line of motion
= component of momentum along perpendicualar to
Angular momentum
After calculation we get
Option 1)
8.64 kg m2s-1
This is an incorrect option.
Option 2)
11.52 kg m2s-1
This is an incorrect option.
Option 3)
14.4 kg m2s-1
This is the correct option.
Option 4)
20.16 kg m2s-1
This is an incorrect option.
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