# A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad s-1, the magnitude of its angular momentum about a point on the ground right under the centre of the circle is : Option 1)   8.64 kg m2s-1   Option 2) 11.52 kg m2s-1   Option 3) 14.4 kg m2s-1   Option 4)   20.16 kg m2s-1

As we learnt

Angular momentum -

- wherein

represent angular momentum of a moving particle about a point.

it can be calculated  as

= Length of perpendicular on line of motion

= component of momentum along perpendicualar to

Angular momentum

After calculation we get

Option 1)

8.64 kg m2s-1

This is an incorrect option.

Option 2)

11.52 kg m2s-1

This is an incorrect option.

Option 3)

14.4 kg m2s-1

This is the correct option.

Option 4)

20.16 kg m2s-1

This is an incorrect option.

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