# If a simple harmonic motion is represented by, its time period is Option 1) Option 2) Option 3) Option 4)

As we learnt in

Equation of S.H.M. -

- wherein

Standard differential equation of SHM is

$\frac{d^{2}x}{dt^{2}}+\omega ^{2}x= 0$

Given equ.is

$\therefore \omega ^{2}= \alpha$

$or \: \: \omega = \sqrt{\alpha }$

$\therefore T= \frac{2\pi }{\omega }= \frac{2\pi }{\sqrt{\alpha }}$

Correct option is 4.

Option 1)

This is an incorrect option.

Option 2)

This is an incorrect option.

Option 3)

This is an incorrect option.

Option 4)

This is the correct option.

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