# A cubical block of side 0.5 m floats on water with 30 % of its volume under water . What is the maximum weight that can be put on the block without fully submerging it under water ? [Take ,density of water =$10^{3}Kg/m^{3}$]Option 1)$46.3Kg$Option 2)$87.5Kg$Option 3)$65.4Kg$Option 4)$30.1Kg$

initial cond:

$B= mg$

$\left ( \rho \right )\left ( \frac{3}{10}Vg \right )=mg$

$\left ( 1000Kg/m^{3} \right )\left ( \frac{3}{10} \times (0.5)^3\right )=m$

$m=37.5Kg$

$finally \, \, \rho vg =\left ( m+M \right )g$

$\frac{\left ( m+M \right )g}{mg}=\frac{\rho Vg }{\rho \times \frac{3}{10}Vg}$

$1+\frac{M}{m}=\frac{10}{3}\Rightarrow \frac{M}{m}=\frac{7}{3}$

$M=\frac{7}{3}\left ( 37.5 \right )=87.3 Kg$

$=87.3 Kg$

Option 1)

$46.3Kg$

Option 2)

$87.5Kg$

Option 3)

$65.4Kg$

Option 4)

$30.1Kg$

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