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  • Answer please! Pure O2 diffuses through an aperture in 224 seconds, whereas mixture of O2 and another gas containing 80% O2 diffuses from the same in 234 seconds. The molecular mass of gas will be

Pure O2 diffuses through an aperture in 224 seconds, whereas mixture of O2 and another gas containing 80% O2 diffuses from the same in 234 seconds. The molecular mass of gas will be 

  • Option 1)

    51.5

  • Option 2)

    48.6

  • Option 3)

    55

  • Option 4)

    46.6

 

Answers (1)

As we learnt in 

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

 

\frac{t_{mix}}{t_{O_{2}}}= \frac{r_{O_{2}}}{r_{mix}}= \sqrt{\frac{M_{mix}}{32}}

\frac{234}{224}= \sqrt{\frac{M_{mix}}{32}}

M_{mix}= 34.92

\Rightarrow \frac{1}{\sqrt{M_{mix}}}= \frac{X_{gas}}{\sqrt{M_{gas}}}+\frac{X_{O_{2}}}{\sqrt{M_{O_{2}}}}

\Rightarrow \frac{1}{\sqrt{34.92}}= \frac{0.2}{\sqrt{M_{gas}}}+\frac{0.8}{\sqrt{32}}

M_{gas} = 51.5


Option 1)

51.5

Correct

Option 2)

48.6

Incorrect

Option 3)

55

Incorrect

Option 4)

46.6

Incorrect

Posted by

Vakul

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