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  2. Answer please! - Redox Reaction and Electrochemistry - JEE Main-4
# Engineering

A solution of Ni(NO_{3})_{2} is electrolysed between platinium electrodes using 0.1 faraday electricity . How many mole of Ni will be deposited at the cathode ?

  • Option 1)

    0.05

  • Option 2)

    0.20

  • Option 3)

    0.15

  • Option 4)

    0.10

Answers (1)
S solutionqc

 

Faraday's first law of electrolysis -

The mass of any substance deposited or dissolved at any electrode during electrolysis is directly propotional to the quantity of electricity passed through the solution.

- wherein

W\alpha\ Q

W = Z I t

Z = mass of electrolyte get deposited

Z = electro chemical equivalent

 

 

 

 

 

 

\\The \:\:reaction \:\:\::\:\:Ni(NO_{3})_{2}\rightarrow Ni^{2+}+2NO_{3}^{-}\\\\\:at\:\:cathode\:\:\:\::Ni^{2+}+2e^{-}\rightarrow Ni 

Ni need 2 mole of  e^{-} for 1 mole of  Ni

0.1\rightarrow \frac{0.1}{2}=0.05\:\:mole


Option 1)

0.05

Option 2)

0.20

Option 3)

0.15

Option 4)

0.10

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