# A solution of $Ni(NO_{3})_{2}$ is electrolysed between platinium electrodes using 0.1 faraday electricity . How many mole of $Ni$ will be deposited at the cathode ? Option 1) $0.05$ Option 2) $0.20$ Option 3) $0.15$ Option 4) $0.10$

Faraday's first law of electrolysis -

The mass of any substance deposited or dissolved at any electrode during electrolysis is directly propotional to the quantity of electricity passed through the solution.

- wherein

$W\alpha\ Q$

W = Z I t

Z = mass of electrolyte get deposited

Z = electro chemical equivalent

$\\The \:\:reaction \:\:\::\:\:Ni(NO_{3})_{2}\rightarrow Ni^{2+}+2NO_{3}^{-}\\\\\:at\:\:cathode\:\:\:\::Ni^{2+}+2e^{-}\rightarrow Ni$

$Ni$ need 2 mole of  $e^{-}$ for 1 mole of  $Ni$

$0.1\rightarrow \frac{0.1}{2}=0.05\:\:mole$

Option 1)

$0.05$

Option 2)

$0.20$

Option 3)

$0.15$

Option 4)

$0.10$

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