What would be the molality of (mass/mass) aqueous solution of KI?
( molar mass of KI = )
Molality (m) = (number of moles of solute)/(mass of solvent in kg)
It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.
Mass percent of solution -
Mass percent = ((mass of solute)/(mass of solution) ) X 100
it is mass of solute present in 100 gram solution.
(mass/mass) = 20 gm is present in 100 gm solution .
solute is KI, weight =20 gm (given)
solvent weight is = 100 - 20 = 80 gm