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Arrange the following coordination compounds in the increasing order of magnetic moments.\text { (Atomic numbers: } \mathrm{Mn}=25 ; \mathrm{Fe}=26 \text { ) }

\mathrm{A} .\left[\mathrm{FeF}_{6}\right]^{3-}

\text { B. }\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}

\text { C. }\left[\mathrm{MnCl}_{6}\right]^{3-} \text { (high spin) }

\text { D. }\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-}

Choose the correct answer from the options given below:

Option: 1

\mathrm{\mathrm{A}<\mathrm{B}<\mathrm{D}<\mathrm{C}}


Option: 2

\mathrm{\mathrm{B}<\mathrm{D}<\mathrm{C}<\mathrm{A}}


Option: 3

\mathrm{\mathrm{A}<\mathrm{C}<\mathrm{D}<\mathrm{B}}


Option: 4

\mathrm{\mathrm{B}<\mathrm{D}<\mathrm{A}<\mathrm{C}}


Answers (1)

best_answer

\mathrm{Fe^{3+}} has \mathrm{d^{5}} configuration

Its configuration is given below:

\mathrm{Mn^{+3}} has \mathrm{d^{4}} configuration

Its configuration is given below:

Hence, the order of magnetic moment is

\mathrm{(A)>(C)>(D)>(B)}

Hence, Option (2) is correct.

Posted by

Ritika Kankaria

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