Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Arrange the following in increasing order of their covalent character.  <img alt="\mathrm{\text { A. } \mathrm{CaF}_{2}}" src="/latex-image/?%5Cmathrm%7B%5Ctext%20%7B%20A.%20%7D%20%5

Arrange the following in increasing order of their covalent character. 

\mathrm{\text { A. } \mathrm{CaF}_{2}}

\mathrm{\text { B. } \mathrm{CaCl}_{2}}

\mathrm{\text { C. } \mathrm{CaBr}_{2}}

\mathrm{\text { D. } \mathrm{CaI}_{2}}

 Choose the correct answer from the options given below. 

Option: 1

\mathrm{B}<\mathrm{A}<\mathrm{C}<\mathrm{D}


Option: 2

\mathrm{A}<\mathrm{B}<\mathrm{C}<\mathrm{D}


Option: 3

\mathrm{A}<\mathrm{B}<\mathrm{D}<\mathrm{C}


Option: 4

\mathrm{A}<\mathrm{C}<\mathrm{B}<\mathrm{D}


Answers (1)

best_answer

According to Fajans rule,

The greater or the larger the size of anion the greater the covalent character of an ionic bond.

Size of anion : \mathrm{I}^{\ominus}>\mathrm{Br}^{\ominus}>\mathrm{Cl}^{\Theta}>\mathrm{F}^{\Theta}

So, covalent character is increasing order -

So,

\\\mathrm{CaF_{2}<CaC_{2}<CaBr_{2}<CaI_{2}}\\\mathrm{A<B<C<D}

Hence, Option (2) is correct.

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Results LIVE: NTA April session result date, time soon; BTech scorecard at jeemain.nta.nic.in
anam-khan

JEE Main 2025 answer key is provisional: NTA says 'drawing conclusions not desirable'
anam-khan

'Students pay for NTA’s mistakes': JEE Main 2025 answer key shows 9 errors, out-of-syllabus questions

Latest Question