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As show in the figure, in steady state, the charge stored in the capacitor is_____________\times 10^{-6} \mathrm{C} \text {. }

Option: 1

10


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

At steady state,there is no current through capacitor

Potential drop across capacitor is

\mathrm{V=IR=\frac{1}{11}\times 100=\frac{100}{11}V}

The change stored in the capacitor is

\mathrm{Q=CV=1.1\times 10^{-6}\times \frac{100}{11}}

\mathrm{Q=10\mu c}

Posted by

Suraj Bhandari

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