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As shown in the figure, P and Q are two co-axial conducting loops separated by some distance. When the switch S is closed, a clockwise current $I_{P}$ flows in P (as seen by E) and an induced current $I_{Q1}$ flows in Q. The switch remains closed for a long time. When S is opened, a current $I_{Q3}$ flows in Q. Then, the directions of $I_{Q1}$ a $I_{Q2}$ (as seen by E) are

Option: 1
respectively clockwise and anti-clockwise

Option: 2
both clockwise

Option: 3
both anti-clockwise

Option: 4
respectively anti-clockwise and clockwise

Answers (1)

When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz’s law, induced current in Q, i.e., $I_{Q1}$ will flow in such a direction, so that the magnetic field lines due to $I_{Q1}$ flows in anti-clockwise direction as seen by E. Opposite is the case when switch S is opened, i.e., $I_{Q2}$ will be clockwise as seen by E.

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