As the s-character of hybridized orbital decreases, the bond angle
Decreases
Increases
Does not change
Becomes zero
As the -character of hybridized orbitals decreases the bond angle also decreases. In
hybridisation:
-character
, bond angle
. In
hybridisation:
-character
, bond angle
. In
hybridisation:
-character
, bond angle
.
Hence, option number (1) is correct
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