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As the s-character of hybridized orbital decreases, the bond angle

Option: 1

Decreases


Option: 2

Increases


Option: 3

Does not change


Option: 4

Becomes zero


Answers (1)

best_answer

As the s-character of hybridized orbitals decreases the bond angle also decreases. In sp^{3} hybridisation: s-character  \frac{1}{4}, bond angle 109^{o} . In sp^{2} hybridisation:
s-character \frac{1}{3}, bond angle 120^{o} . In sp hybridisation: s-character \frac{1}{2}, bond angle 180^{o} .
Hence, option number (1) is correct

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