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  • Assuming that the rings are identical except for the difference in colors, the number of ways in which one or more balls can be chosen from a set of 4 black, 6 blue, and 5 red rings is</p

Assuming that the rings are identical except for the difference in colors, the number of ways in which one or more balls can be chosen from a set of 4 black, 6 blue, and 5 red rings is

Option: 1

109


Option: 2

210


Option: 3

312


Option: 4

209


Answers (1)

best_answer

Given that,

The different types of balls are 4 black balls, 6 blue balls, and 5 red balls.

The total number of balls is 15 balls.

The number of black balls = 4.

The number of blue balls = 6.

The number of red balls = 5.

The formula to find the number of ways of selection is given by,

\begin{aligned} & N=(p+1) \times(q+1) \times(r+1)-1 \\ & N=(4+1) \times(6+1) \times(5+1)-1 \\ & N=(5 \times 7 \times 6)-1 \\ & N=210-1 \\ & N=209 \end{aligned}

Therefore, the number of ways of arranging the rings is 209 ways.

 

Posted by

shivangi.shekhar

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