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  • Assuming the balls to be identical except for difference of colours the number of ways in which one or more ball can be selected from 10 white, 9 green and 7 black balls is:<div class='qna-opti

Assuming the balls to be identical except for difference of colours the number of ways in which one or more ball can be selected from 10 white, 9 green and 7 black balls is:

Option: 1

629


Option: 2

630


Option: 3

879


Option: 4

880


Answers (1)

best_answer

We can select 0 or more balls out of 10 white balls in 11 ways. [select0 \: or \: 1\: or \: 2 \cdots or 10 white balls.] Thus, the number of ways of making a selection of 0 or more balls

=(1+10)(1+9)(1+7)=880

Therefore, number of ways of selecting at least one ball =880-1=879.

Posted by

Shailly goel

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