# At 1 atm , pressure Delta S = 75 JK^{-1}mol^{-1}, 30 KJ: mol^{-1} then value of Delta G at 100 k will be :-

Answers (1)

Given , $\Delta S = 75 J K^{-1}mol^{-1}$

$\Delta H = 30 KJ mol^{-1}$

$\Delta G = \Delta H - T\Delta S$

$\Delta G = 30\times 10^{3} - 100\times 75$

$\Delta G = 22500 \; Jmol^{-1}$

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